Solve for [tex]x[/tex].

[tex]\[ 3x = 6x - 2 \][/tex]

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What is the point-slope form of a line with slope 3 that contains the point [tex]\((2, 1)\)[/tex]?

A. [tex]\(y - 1 = 3(x - 2)\)[/tex]



Answer :

To determine the point-slope form of a line that has a given slope and passes through a specific point, we use the point-slope formula of a linear equation, which is:

[tex]\[ y - y_1 = m(x - x_1) \][/tex]

Here, [tex]\((x_1, y_1)\)[/tex] is a point on the line, and [tex]\(m\)[/tex] is the slope of the line.

In this problem, we are given:
- The slope [tex]\( m = 3 \)[/tex]
- The point [tex]\( (x_1, y_1) = (2, 1) \)[/tex]

We substitute these values into the point-slope formula:

[tex]\[ y - 1 = 3(x - 2) \][/tex]

Therefore, the point-slope form of the line with slope [tex]\(3\)[/tex] that passes through the point [tex]\((2, 1)\)[/tex] is:

[tex]\[ y - 1 = 3(x - 2) \][/tex]

So, the correct answer is not [tex]\( y - 2 = 3(x - 1) \)[/tex], rather it is [tex]\( y - 1 = 3(x - 2) \)[/tex].

Thus, the provided answer "A. [tex]\( y - 2 = 3(x - 1) \)[/tex]" is incorrect. The correct point-slope form of the line is:

[tex]\[ y - 1 = 3(x - 2) \][/tex]