Answer :
Answer:
C) (x+1)(5x-2)
Step-by-step explanation:
Solving the Problem
We can rearrange the terms in the polynomial to maximize our factoring.
Since [tex]5x^2[/tex] and [tex]5x[/tex] both have "5" and an x in their term and [tex]-2x[/tex] and [tex]-2[/tex] both have "-2" in their term we can swap -2x and +5x so that they're next to their respective terms.
[tex]5x^2+5x-2x-2[/tex]
[tex]\dotfill[/tex]
Factoring the Problem
Between the two leftmost terms, we can factor out a 5 and an x, this leaves
[tex]5x(x+1)-2x-2[/tex].
Factoring out -2 from the rightmost terms we have,
[tex]5x(x+1)-2(x+1)[/tex].
Since both the left and right sides have (x+1), we can factor it from this new expression.
[tex](x+1)\leftbig(5x-2)[/tex]
So, C is our final answer.
The factoring of the expression is C) (x+1)(5x-2).
To factor the expression 5x² - 2x + 5x - 2 by grouping, follow these steps:
Group the terms to find common factors:
(5x² - 2x) + (5x - 2)
Factor out the greatest common factor (GCF) from each group:
x(5x - 2) + 1(5x - 2)
Factor out the common binomial factor:
(5x - 2)(x + 1)
