Solve for [tex][tex]$x$[/tex][/tex].

[tex]\[ 3x = 6x - 2 \][/tex]



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[tex]\[ \frac{15}{\pi r_1^2} = \frac{F_2}{\pi (16 r_1^2)} \][/tex]



Answer :

To solve the equation [tex]\(\frac{15}{\pi r_1^2}=\frac{F_2}{\pi (16 r_1^2)}\)[/tex], follow these steps:

1. Simplify the constants in the equation:

Starting with the given equation:
[tex]\[ \frac{15}{\pi r_1^2} = \frac{F_2}{\pi (16 r_1^2)} \][/tex]

2. Cancel out the common terms:

Since [tex]\(\pi r_1^2\)[/tex] appears in both denominators, we can cancel them out for simplicity:
[tex]\[ \frac{15}{r_1^2} = \frac{F_2}{16 r_1^2} \][/tex]

3. Multiply both sides by [tex]\(r_1^2\)[/tex] to eliminate the [tex]\(r_1^2\)[/tex] terms:

Multiplying both sides by [tex]\(r_1^2\)[/tex] results in:
[tex]\[ 15 = \frac{F_2}{16} \][/tex]

4. Isolate [tex]\(F_2\)[/tex]:

To solve for [tex]\(F_2\)[/tex], multiply both sides of the equation by 16:
[tex]\[ 15 \times 16 = F_2 \][/tex]

5. Perform the multiplication:

Calculating the left-hand side:
[tex]\[ 15 \times 16 = 240 \][/tex]

6. Write the final solution:

Hence, the value of [tex]\(F_2\)[/tex] is:
[tex]\[ F_2 = 240 \][/tex]

This gives us the result:
[tex]\[ \boxed{240} \][/tex]