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Consider the following intermediate chemical equations:

[tex]\[
\begin{array}{l}
2 H_2(g) + O_2(g) \rightarrow 2 H_2O(l) \\
H_2(g) + F_2(g) \rightarrow 2 HF(g)
\end{array}
\][/tex]

In the final chemical equation, [tex]$HF$[/tex] and [tex]$O_2$[/tex] are the products that are formed through the reaction between [tex]$H_2O$[/tex] and [tex]$F_2$[/tex]. Before you can add these intermediate chemical equations, you need to alter them by:

A. Multiplying the second equation by 2 and reversing the first equation.
B. Multiplying the first equation by 2 and reversing it.
C. Multiplying the first equation by [tex]\( \frac{1}{2} \)[/tex] and reversing the second equation.
D. Multiplying the second equation by 2 and reversing it.



Answer :

GinnyAnswer
Let's outline a detailed, step-by-step solution to transform and combine these intermediate chemical equations according to the given instructions:

1. Initial Equations:
- Equation 1: [tex]\( 2 H_2(g) + O_2(g) \rightarrow 2 H_2O(l) \)[/tex]
- Equation 2: [tex]\( H_2(g) + F_2(g) \rightarrow 2 HF(g) \)[/tex]

2. Alter Equation 2 by Multiplying It by 2:
- Original Equation 2: [tex]\( H_2(g) + F_2(g) \rightarrow 2 HF(g) \)[/tex]
- Multiply all coefficients by 2:
[tex]\[ 2[H_2(g) + F_2(g)] \rightarrow 4 HF(g) \][/tex]
- The simplified form is:
[tex]\[ 2 H_2(g) + 2 F_2(g) \rightarrow 4 HF(g) \][/tex]

3. Reverse Equation 1:
- Original Equation 1: [tex]\( 2 H_2(g) + O_2(g) \rightarrow 2 H_2O(l) \)[/tex]
- Reverse the equation:
[tex]\[ 2 H_2O(l) \rightarrow 2 H_2(g) + O_2(g) \][/tex]

4. Resulting Altered Equations:
- Altered Equation 1 (Reversed): [tex]\( 2 H_2O(l) \rightarrow 2 H_2(g) + O_2(g) \)[/tex]
- Altered Equation 2 (Multiplied by 2): [tex]\( 2 H_2(g) + 2 F_2(g) \rightarrow 4 HF(g) \)[/tex]

Therefore, based on the given instructions, we have:
[tex]\[ 2 H_2O(l) \rightarrow 2 H_2(g) + O_2(g) \][/tex]
[tex]\[ 2 H_2(g) + 2 F_2(g) \rightarrow 4 HF(g) \][/tex]

The final forms of the altered equations are:
- Equation 1: [tex]\( 2 H_2O(l) \rightarrow 2 H_2(g) + O_2(g) \)[/tex]
- Equation 2: [tex]\( 2 H_2(g) + 2 F_2(g) \rightarrow 4 HF(g) \)[/tex]

These are the intermediates needed to form the desired chemical reaction with [tex]\(HF\)[/tex] and [tex]\(O_2\)[/tex] as the products using [tex]\(H_2O\)[/tex] and [tex]\(F_2\)[/tex].

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