Consider the geometric sequence below.
[tex]\[ -21, 63, -189, 567, \ldots \][/tex]

Complete the recursively defined function to describe this sequence.

Numbers to use:
-21, -3, 3

[tex]\[
\begin{aligned}
f(1) &= -21 \\
f(n) &= -3 f(n-1) \quad \text{for} \quad n = 2, 3, 4, \ldots
\end{aligned}
\][/tex]



Answer :

Certainly! Let's define the recursively defined function to describe the given geometric sequence:

The sequence provided is:
[tex]\[ -21, 63, -189, 567, \ldots \][/tex]

### Determining the first term ([tex]\(a_1\)[/tex]):
The first term of the sequence ([tex]\(a_1\)[/tex]) is [tex]\( -21 \)[/tex].

### Identifying the common ratio:
To determine the common ratio, we divide the second term by the first term, the third term by the second term, and so on to confirm consistency.
[tex]\[ \frac{63}{-21} = -3 \][/tex]
[tex]\[ \frac{-189}{63} = -3 \][/tex]
[tex]\[ \frac{567}{-189} = -3 \][/tex]
We see that the common ratio is [tex]\( -3 \)[/tex].

### Formulating the recursive function:
We can now complete the recursive function definition for this sequence. The recursive definition has two parts: the base case and the recursive case.

#### Base Case:
[tex]\( f(1) \)[/tex] is the first term of the sequence.
[tex]\[ f(1) = -21 \][/tex]

#### Recursive Case:
For [tex]\( n \geq 2 \)[/tex], each term is obtained by multiplying the previous term [tex]\( f(n-1) \)[/tex] by the common ratio [tex]\( -3 \)[/tex].
[tex]\[ f(n) = -3 \cdot f(n-1) \quad \text{for} \; n = 2, 3, 4, \ldots \][/tex]

### Final Formulation of the Recursive Function:
[tex]\[ f(1) = -21 \][/tex]
[tex]\[ f(n) = -3 \cdot f(n-1) \quad \text{for} \; n = 2, 3, 4, \ldots \][/tex]

### Completion:
Therefore, the complete recursively defined function for the geometric sequence is:

[tex]\[ f(1) = -21 \][/tex]
[tex]\[ f(n) = -3 \cdot f(n-1) \quad \text{for} \; n = 2, 3, 4, \ldots \][/tex]

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