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Robert is a 15-year-old boy. His recommended dietary intake for vitamins B12, C, and E is [tex]2.4 \mu g/day[/tex], [tex]75 mg/day[/tex], and [tex]15 mg/day[/tex], respectively. He eats a salmon fillet with one cup of boiled green beans and half a cup of fresh sliced strawberries for lunch. If the nutrient values of his meal components are as shown below, for which vitamins did Robert meet at least [tex]75\%[/tex] of his recommended daily allowance?

\begin{tabular}{|l|l|l|l|}
\hline
& Vitamin B12 & Vitamin C & Vitamin E \\
\hline
salmon fillet (124 g) & [tex]$5.87 \mu g$[/tex] & [tex]$0.0 mg$[/tex] & [tex]$0.60 mg$[/tex] \\
\hline
boiled green beans (1 cup) & [tex]$0.0 \mu g$[/tex] & [tex]$12.1 mg$[/tex] & [tex]$0.57 mg$[/tex] \\
\hline
strawberries, sliced (1/2 cup) & [tex]$0.0 \mu g$[/tex] & [tex]$49.0 mg$[/tex] & [tex]$0.42 mg$[/tex] \\
\hline
\end{tabular}

A. Vitamin B12, Vitamin C, and Vitamin E
B. Vitamin B12 and Vitamin C only
C. Vitamin B12 and Vitamin E only
D. Vitamin C and Vitamin E only
E. Vitamin B12 only



Answer :

GinnyAnswer
To determine which vitamins Robert met at least 75% of his recommended daily allowance, we need to find the totals of each vitamin in his lunch and then calculate the percentages of the recommended intake these totals represent.

First, let's summarize the nutrient values in Robert's lunch:

- Salmon Fillet:
- Vitamin B12: 5.87 µg
- Vitamin C: 0.0 mg
- Vitamin E: 0.60 mg

- Boiled Green Beans (1 cup):
- Vitamin B12: 0.0 µg
- Vitamin C: 12.1 mg
- Vitamin E: 0.57 mg

- Strawberries, Sliced (1/2 cup):
- Vitamin B12: 0.0 µg
- Vitamin C: 49.0 mg
- Vitamin E: 0.42 mg

Next, we calculate the total intake of each vitamin from this meal:

- Total Vitamin B12:
[tex]\[ 5.87 \mu g + 0.0 \mu g + 0.0 \mu g = 5.87 \mu g \][/tex]

- Total Vitamin C:
[tex]\[ 0.0 mg + 12.1 mg + 49.0 mg = 61.1 mg \][/tex]

- Total Vitamin E:
[tex]\[ 0.60 mg + 0.57 mg + 0.42 mg = 1.59 mg \][/tex]

Now, we calculate the percentages of the recommended daily allowances represented by these totals:

- Percentage of Vitamin B12:
[tex]\[ \left(\frac{5.87 \mu g}{2.4 \mu g}\right) \times 100 \approx 244.58 \% \][/tex]

- Percentage of Vitamin C:
[tex]\[ \left(\frac{61.1 mg}{75 mg}\right) \times 100 \approx 81.47 \% \][/tex]

- Percentage of Vitamin E:
[tex]\[ \left(\frac{1.59 mg}{15 mg}\right) \times 100 \approx 10.6 \% \][/tex]

Finally, we determine which of these percentages are at least 75% of the recommended intake:

- Vitamin B12: [tex]\(244.58\%\)[/tex] which is indeed >= 75%
- Vitamin C: [tex]\(81.47\%\)[/tex] which is also >= 75%
- Vitamin E: [tex]\(10.6\%\)[/tex] which is less than 75%

Therefore, Robert met at least 75% of his recommended daily allowance for Vitamin B12 and Vitamin C only.

The correct answer is:
B. vitamin B12 and vitamin C only