Answer :
To solve for the ratio of sodium (Na) to element "Z" in compound B, follow these steps:
1. Identify the given masses:
- The mass of sodium (Na) in compound B is 3.45 grams.
- The mass of element Z in compound B is 0.700 grams.
2. Determine the ratio:
- The ratio of sodium (Na) to element Z is calculated by dividing the mass of sodium by the mass of element Z.
[tex]\[ \text{Ratio (Na to Z)} = \frac{\text{Mass of Na}}{\text{Mass of element Z}} \][/tex]
[tex]\[ \text{Ratio (Na to Z)} = \frac{3.45\text{ grams}}{0.700\text{ grams}} \][/tex]
3. Calculate the ratio:
[tex]\[ \frac{3.45}{0.700} \approx 4.93 \][/tex]
So, the ratio of sodium to element Z for compound B is approximately 4.93:1. This means that in compound B, for every 1 part of element Z, there are approximately 4.93 parts of sodium.
1. Identify the given masses:
- The mass of sodium (Na) in compound B is 3.45 grams.
- The mass of element Z in compound B is 0.700 grams.
2. Determine the ratio:
- The ratio of sodium (Na) to element Z is calculated by dividing the mass of sodium by the mass of element Z.
[tex]\[ \text{Ratio (Na to Z)} = \frac{\text{Mass of Na}}{\text{Mass of element Z}} \][/tex]
[tex]\[ \text{Ratio (Na to Z)} = \frac{3.45\text{ grams}}{0.700\text{ grams}} \][/tex]
3. Calculate the ratio:
[tex]\[ \frac{3.45}{0.700} \approx 4.93 \][/tex]
So, the ratio of sodium to element Z for compound B is approximately 4.93:1. This means that in compound B, for every 1 part of element Z, there are approximately 4.93 parts of sodium.
