Solve for [tex]\( x \)[/tex]:

[tex]\[ 3x = 6x - 2 \][/tex]



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[tex]$d e+1 a=d e s$[/tex]
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Response:
Simplify the expression:

[tex]\[ d \cdot e + 1 \cdot a = d \cdot e \cdot s \][/tex]