Answer :
To solve the problem of finding the probability that a randomly selected car with no 4-wheel drive has third-row seats, let's break it down step by step.
1. Identify the total number of cars with no 4-wheel drive:
From the table, the column labeled "No 4-Wheel Drive" shows the total number of such cars:
[tex]\[ \text{Total number of cars with no 4-wheel drive} = 40 \][/tex]
2. Identify the number of cars with no 4-wheel drive that also have third-row seats:
From the same column, we see the entry in the row labeled "Third-Row Seats", which gives us the count:
[tex]\[ \text{Number of no 4-wheel drive cars with third-row seats} = 12 \][/tex]
3. Calculate the probability:
The probability of an event can be found by dividing the number of favorable outcomes by the total number of outcomes. In this case, it's the number of no 4-wheel drive cars with third-row seats divided by the total number of no 4-wheel drive cars:
[tex]\[ \text{Probability} = \frac{\text{Number of no 4-wheel drive cars with third-row seats}}{\text{Total number of no 4-wheel drive cars}} = \frac{12}{40} \][/tex]
4. Simplify the fraction:
To make the fraction easier to interpret,
[tex]\[ \frac{12}{40} = 0.3 \][/tex]
5. Match the probability with the given choices:
The probability that a randomly selected car with no 4-wheel drive has third-row seats is [tex]\(0.3\)[/tex].
Thus, the correct answer is:
[tex]\[ 0.3 \][/tex]
1. Identify the total number of cars with no 4-wheel drive:
From the table, the column labeled "No 4-Wheel Drive" shows the total number of such cars:
[tex]\[ \text{Total number of cars with no 4-wheel drive} = 40 \][/tex]
2. Identify the number of cars with no 4-wheel drive that also have third-row seats:
From the same column, we see the entry in the row labeled "Third-Row Seats", which gives us the count:
[tex]\[ \text{Number of no 4-wheel drive cars with third-row seats} = 12 \][/tex]
3. Calculate the probability:
The probability of an event can be found by dividing the number of favorable outcomes by the total number of outcomes. In this case, it's the number of no 4-wheel drive cars with third-row seats divided by the total number of no 4-wheel drive cars:
[tex]\[ \text{Probability} = \frac{\text{Number of no 4-wheel drive cars with third-row seats}}{\text{Total number of no 4-wheel drive cars}} = \frac{12}{40} \][/tex]
4. Simplify the fraction:
To make the fraction easier to interpret,
[tex]\[ \frac{12}{40} = 0.3 \][/tex]
5. Match the probability with the given choices:
The probability that a randomly selected car with no 4-wheel drive has third-row seats is [tex]\(0.3\)[/tex].
Thus, the correct answer is:
[tex]\[ 0.3 \][/tex]
