To determine the probability of having green and wrinkled seeds from a dihybrid cross RrYy x RrYy, follow these steps:
1. Understand the phenotypes and genotypes:
- Round (R) and wrinkled (r) seeds represent one trait (shape).
- Yellow (Y) and green (y) seeds represent another trait (color).
- R and Y are dominant alleles, while r and y are recessive alleles.
2. Establish the parental genotypes:
- Both parents in the cross are RrYy.
3. Determine the possible gametes:
- Each parent can produce four types of gametes due to the assortment of the alleles: RY, Ry, rY, ry.
4. Create a Punnett Square:
- A 4x4 Punnett square helps to identify all potential combinations of these gametes (16 possible genotypes).
5. Analyze the offspring phenotypes:
- We are interested in the green and wrinkled seeds, which correspond to the genotype rryy.
6. Calculate the probability:
- Examine the Punnett square and count how many times the genotype rryy appears among the 16 possible genotypes.
- The result will show that rryy appears once.
Thus, the probability of having green and wrinkled seeds (rryy) is:
[tex]\[ \frac{1}{16} \][/tex]
Which can also be written as:
[tex]\[ 1:16 \][/tex]
Therefore, the correct answer is 1:16.
