If [tex][tex]$U=\{x: x$[/tex] is a positive integer [tex]$\ \textless \ 20\}$[/tex][/tex] and [tex][tex]$A=\{y: y$[/tex] is a multiple of 4\}[tex]$[/tex], then [tex]$[/tex]n(U \cup A) = \ldots?$[/tex]

A. 8
B. 5
C. 55
D. 0
E. None



Answer :

To find the number of elements in the union of two sets [tex]\( U \)[/tex] and [tex]\( A \)[/tex], we start by understanding the sets individually.

1. Set [tex]\( U \)[/tex]: This set includes all positive integers less than 20. So, [tex]\[ U = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19\} \][/tex]

2. Set [tex]\( A \)[/tex]: This set consists of all multiples of 4 within the same range. Therefore, [tex]\[ A = \{4, 8, 12, 16\} \][/tex]

Next, we proceed to find the union of these two sets, which includes all distinct elements from both sets combined.

[tex]\[ U \cup A = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19\} \][/tex]

Notice that elements in [tex]\( A \)[/tex] are already included in the complete list of [tex]\( U \)[/tex]. Thus, the union does not add any new elements beyond those already in [tex]\( U \)[/tex].

Finally, count the number of distinct elements in the union set [tex]\( U \cup A \)[/tex]:

[tex]\[ n(U \cup A) = 19 \][/tex]

Therefore, the number of elements in the union of [tex]\( U \)[/tex] and [tex]\( A \)[/tex] is given by:

[tex]\[ \boxed{19} \][/tex]