Solve for [tex]a[/tex]:
[tex]6a + 7a - 8 = 4a[/tex]

Select one:
a. [tex]\frac{12}{13}[/tex]
b. [tex]\frac{8}{9}[/tex]
c. [tex]\frac{9}{8}[/tex]
d. [tex]-\frac{4}{3}[/tex]



Answer :

Okay, let's solve the given equation step-by-step:

We start with the given equation:
[tex]\[ 6a + 7a - 8 = 4a \][/tex]

First, we need to combine like terms on the left side of the equation. Adding [tex]\(6a\)[/tex] and [tex]\(7a\)[/tex] gives us:
[tex]\[ 13a - 8 = 4a \][/tex]

Next, we need to isolate the variable [tex]\(a\)[/tex]. To do this, we can start by subtracting [tex]\(4a\)[/tex] from both sides of the equation:
[tex]\[ 13a - 4a - 8 = 4a - 4a \][/tex]

This simplifies to:
[tex]\[ 9a - 8 = 0 \][/tex]

Now, we want to isolate [tex]\(9a\)[/tex]. To do this, we add 8 to both sides of the equation:
[tex]\[ 9a - 8 + 8 = 0 + 8 \][/tex]

Simplifying this, we get:
[tex]\[ 9a = 8 \][/tex]

Next, we solve for [tex]\(a\)[/tex] by dividing both sides of the equation by 9:
[tex]\[ a = \frac{8}{9} \][/tex]

So, the solution to the equation is
[tex]\[ a = \frac{8}{9} \][/tex]

Therefore, the correct answer is:
b. [tex]\(\frac{8}{9}\)[/tex]