Given this balanced reaction:

[tex]\[ \text{Al}_2\text{O}_3(s) + 3 \text{CO}(g) \rightarrow 2 \text{Al}(s) + 3 \text{CO}_2(g) \][/tex]

If 2.66 grams of Al(s) were produced, how many liters of CO2(g) were produced at STP?

1. What is the first step or conversion factor?
[tex]\[ \frac{26.98 \, \text{g Al}}{1 \, \text{mol Al}} \][/tex]

2. What is the second step or conversion factor?
[Select]

3. What is the third step or conversion factor?
[Select]

4. What is the fourth step or conversion factor?
[Select]

5. What is the final answer?



Answer :

To solve this problem, let’s follow the steps one by one:

1) What is the first step or conversion factor?
- The first step is to convert the given mass of aluminum (Al) to moles of Al using the molar mass of Al.

Conversion factor:
[tex]\[ \text{(26.98 g Al / 1 mol Al)} \][/tex]

2) What is the second step or conversion factor?
- The next step is to use the stoichiometric ratio from the balanced chemical equation to convert moles of Al to moles of CO2.

Conversion factor:
[tex]\[ \text{(3 moles CO2 / 2 moles Al)} \][/tex]

3) What is the third step or conversion factor?
- Then, we need to convert moles of CO2 to volume of CO2 at STP using the molar volume of gas at STP.

Conversion factor:
[tex]\[ \text{(22.4 L CO2 / 1 mol CO2)} \][/tex]

4) What is the fourth step or conversion factor?
- Following the procedure in sequence ensures we’re converting the units step-by-step to get the final volume of CO2.

5) What is the final answer?
- After completing the calculations, the volume of CO2 produced at STP is found to be:

[tex]\[ 3.31 \, \text{liters} \][/tex]