To determine the pOH of the solution given that the concentration of hydroxide ions, [tex]\([OH^-]\)[/tex], is 0.00500 M, we can follow these steps:
1. Identify the formula for pOH:
[tex]\[
\text{pOH} = -\log_{10}[\text{OH}^-]
\][/tex]
2. Insert the concentration of [tex]\([\text{OH}^-]\)[/tex]:
[tex]\[
[\text{OH}^-] = 0.00500\text{ M}
\][/tex]
3. Calculate the pOH:
[tex]\[
\text{pOH} = -\log_{10}(0.00500)
\][/tex]
Performing the logarithmic calculation:
[tex]\[
\text{pOH} = -\log_{10}(0.00500) \approx 2.30
\][/tex]
Thus, the pOH of the solution is approximately 2.30.
Therefore, the correct answer is:
[tex]\[
\boxed{2.30}
\][/tex]
