What is the probability that a randomly selected car is a two-door hybrid?

\begin{tabular}{|l|c|c|c|}
\cline{2-4}
\multicolumn{1}{c|}{} & Hybrid & Not a hybrid & Total \\
\hline
Two-Door & 14 & 5 & 19 \\
\hline
Four-Door & 7 & 21 & 28 \\
\hline
Total & 21 & 26 & 47 \\
\hline
\end{tabular}

Express the probability as a percent rounded to the nearest tenth of a percent.

Enter your answer in the box.
[tex]$\square$[/tex] \%



Answer :

To solve this problem, let’s find the probability that a randomly selected car is a two-door hybrid using the given data.

1. Identify the total number of two-door hybrid cars:
- From the table, the number of two-door hybrid cars is [tex]\( 14 \)[/tex].

2. Identify the total number of cars:
- The total number of cars is the sum of all the frequencies in the table. Adding these, we get:
[tex]\[ 19 (\text{two-door} \text{ + both hybrid and not hybrid}) + 28 (\text{four-door} \text{ + both hybrid and not hybrid}) = 47 \][/tex]

3. Calculate the probability:
- The probability that a randomly selected car is a two-door hybrid is found by dividing the number of two-door hybrid cars by the total number of cars:
[tex]\[ \frac{14}{47} \][/tex]

4. Convert the probability to a percentage:
- To convert the fraction to a percentage, we multiply by 100:
[tex]\[ \left( \frac{14}{47} \right) \times 100 \approx 29.78723404255319 \% \][/tex]

5. Round the result to the nearest tenth percent:
- To round 29.78723404255319 to the nearest tenth, we look at the second digit after the decimal point. Since it is 8, we round up:
[tex]\[ \approx 29.8\% \][/tex]

Thus, the probability that a randomly selected car is a two-door hybrid, expressed as a percentage rounded to the nearest tenth of a percent, is [tex]\( \boxed{29.8\%} \)[/tex].