Which choice is equivalent to the product below when [tex][tex]$x \geq 0$[/tex][/tex]?

[tex]\sqrt{6 x^2} \cdot \sqrt{18 x^2}[/tex]

A. [tex]6 \sqrt{3 x}[/tex]

B. [tex]6 \sqrt{18 x}[/tex]

C. [tex]6 x^2 \sqrt{3}[/tex]

D. [tex]\sqrt{108 x^2}[/tex]



Answer :

To find the equivalent expression for the product [tex]\(\sqrt{6 x^2} \cdot \sqrt{18 x^2}\)[/tex], follow these steps:

1. Use the property of square roots:
We know that [tex]\(\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}\)[/tex]. Therefore,
[tex]\[ \sqrt{6 x^2} \cdot \sqrt{18 x^2} = \sqrt{(6 x^2) \cdot (18 x^2)}. \][/tex]

2. Calculate the product inside the square root:
Multiply the terms inside the square root:
[tex]\[ 6 x^2 \cdot 18 x^2 = 108 x^4. \][/tex]

3. Simplify the expression:
Now, we have [tex]\(\sqrt{108 x^4}\)[/tex]. We can simplify this further by factoring 108 as [tex]\(36 \cdot 3\)[/tex]:
[tex]\[ \sqrt{108 x^4} = \sqrt{36 \cdot 3 \cdot x^4}. \][/tex]

4. Separate the square root for easier computation:
Recognize that [tex]\(\sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b}\)[/tex]. Thus,
[tex]\[ \sqrt{36 \cdot 3 \cdot x^4} = \sqrt{36} \cdot \sqrt{3} \cdot \sqrt{x^4}. \][/tex]

5. Simplify each square root:
[tex]\(\sqrt{36} = 6\)[/tex] and [tex]\(\sqrt{x^4} = x^2\)[/tex] (since [tex]\(x \geq 0\)[/tex], we can directly take the square root):
[tex]\[ \sqrt{36} \cdot \sqrt{3} \cdot \sqrt{x^4} = 6 \cdot \sqrt{3} \cdot x^2. \][/tex]

6. Combine the simplified terms:
Therefore, the expression simplifies to:
[tex]\[ 6 x^2 \sqrt{3}. \][/tex]

By following the steps, we determine that the equivalent expression is [tex]\(6 x^2 \sqrt{3}\)[/tex].

Thus, the correct answer is:
[tex]\[ \boxed{6 x^2 \sqrt{3}}. \][/tex]