Miguel elige dos números: uno de tres dígitos y otro de dos dígitos. La diferencia de esos números es 989.

¿Cuál es la suma de los números elegidos por Miguel?

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GinnyAnswer GinnyAnswer · Answer 1 · 2024-06-25T21:47:36-04:00

The answer provides a method to determine the two numbers chosen by Miguel and calculates their sum.

To find the two numbers chosen by Miguel, one with three digits and the other with two digits, given their difference is 989:

Let's assume the three-digit number is ABC and the two-digit number is DE. This leads to the equation 100A + 10B + C - 10D - E = 989.
From this, we know that A = 1 and E = 9 to have the difference of 989. By trial and error, you can determine B, C, and D.
The sum of the numbers chosen by Miguel, ABC and DE, can then be found by adding these values together.

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