Answer :
To determine the momentum of a given object, we use the formula:
[tex]\[ \text{Momentum} = \text{mass} \times \text{velocity} \][/tex]
In this particular problem:
- The mass of the van is \( 1.5 \times 10^3 \) kilograms.
- The velocity of the van is 32 meters/second.
Let's calculate the momentum step by step.
1. Identify the mass of the van:
[tex]\[ \text{mass} = 1.5 \times 10^3 \text{ kilograms} \][/tex]
2. Identify the velocity of the van:
[tex]\[ \text{velocity} = 32 \text{ meters/second} \][/tex]
3. Multiply the mass by the velocity to find the momentum:
[tex]\[ \text{Momentum} = (1.5 \times 10^3) \times 32 \][/tex]
When you multiply these values, you get:
[tex]\[ 1.5 \times 10^3 \times 32 = 48000.0 \text{ kilogram meters/second} \][/tex]
Thus, the momentum of the van is:
[tex]\[ 48000.0 \text{ kilogram meters/second} \][/tex]
Now, looking at the answers provided:
A. 46.9 kilogram meters/second
B. [tex]$4.7 \times 10^3$[/tex] kilogram meters/second
C. [tex]$4.85 \times 10^2$[/tex] kilogram meters/second
D. [tex]$4.85 \times 10^4$[/tex] kilogram meters/second
The correct answer matches the calculated value:
[tex]\[ D. 4.85 \times 10^4 \text{ Kilogram meters/second} \][/tex]
However, note that the correct scientific notation should be [tex]$4.8 \times 10^4$[/tex], but the correct choice among the given options closest to our result is:
[tex]\[ D. 4.85 \times 10^4 \text{ Kilogram meters/second} \][/tex]
[tex]\[ \text{Momentum} = \text{mass} \times \text{velocity} \][/tex]
In this particular problem:
- The mass of the van is \( 1.5 \times 10^3 \) kilograms.
- The velocity of the van is 32 meters/second.
Let's calculate the momentum step by step.
1. Identify the mass of the van:
[tex]\[ \text{mass} = 1.5 \times 10^3 \text{ kilograms} \][/tex]
2. Identify the velocity of the van:
[tex]\[ \text{velocity} = 32 \text{ meters/second} \][/tex]
3. Multiply the mass by the velocity to find the momentum:
[tex]\[ \text{Momentum} = (1.5 \times 10^3) \times 32 \][/tex]
When you multiply these values, you get:
[tex]\[ 1.5 \times 10^3 \times 32 = 48000.0 \text{ kilogram meters/second} \][/tex]
Thus, the momentum of the van is:
[tex]\[ 48000.0 \text{ kilogram meters/second} \][/tex]
Now, looking at the answers provided:
A. 46.9 kilogram meters/second
B. [tex]$4.7 \times 10^3$[/tex] kilogram meters/second
C. [tex]$4.85 \times 10^2$[/tex] kilogram meters/second
D. [tex]$4.85 \times 10^4$[/tex] kilogram meters/second
The correct answer matches the calculated value:
[tex]\[ D. 4.85 \times 10^4 \text{ Kilogram meters/second} \][/tex]
However, note that the correct scientific notation should be [tex]$4.8 \times 10^4$[/tex], but the correct choice among the given options closest to our result is:
[tex]\[ D. 4.85 \times 10^4 \text{ Kilogram meters/second} \][/tex]
