Answer :
Let's start with the mass of the dust particle, which is given as \(0.000000000778\) kg.
We need to express this number in scientific notation, which is of the form \(a \times 10^b\).
So, the mass of the dust particle in scientific notation is:
[tex]\[ 7.78 \times 10^{-10} \, \text{kg} \][/tex]
Thus, for the dust particle:
- \(a\) is \(7.78\)
- \(b\) is \(-10\)
Next, let's consider the mass of the comet, which is given as \(544000000000000\) kg.
Again, we need to express this number in scientific notation.
So, the mass of the comet in scientific notation is:
[tex]\[ 5.44 \times 10^{14} \, \text{kg} \][/tex]
Thus, for the comet:
- \(a\) is \(5.44\)
- \(b\) is \(14\)
Therefore, the filled-in blanks based on the table would be:
For the dust particle:
- \(a = 7.78\)
- \(b = -10\)
For the comet:
- \(a = 5.44\)
- [tex]\(b = 14\)[/tex]
We need to express this number in scientific notation, which is of the form \(a \times 10^b\).
So, the mass of the dust particle in scientific notation is:
[tex]\[ 7.78 \times 10^{-10} \, \text{kg} \][/tex]
Thus, for the dust particle:
- \(a\) is \(7.78\)
- \(b\) is \(-10\)
Next, let's consider the mass of the comet, which is given as \(544000000000000\) kg.
Again, we need to express this number in scientific notation.
So, the mass of the comet in scientific notation is:
[tex]\[ 5.44 \times 10^{14} \, \text{kg} \][/tex]
Thus, for the comet:
- \(a\) is \(5.44\)
- \(b\) is \(14\)
Therefore, the filled-in blanks based on the table would be:
For the dust particle:
- \(a = 7.78\)
- \(b = -10\)
For the comet:
- \(a = 5.44\)
- [tex]\(b = 14\)[/tex]