Solve for [tex]$x[tex]$[/tex] and [tex]$[/tex]y$[/tex]:

[tex]\[
\begin{array}{l}
x = 5 - 2y \\
6y = 10 - 3x
\end{array}
\][/tex]



Answer :

Certainly! Let's solve the system of equations step-by-step:

We have two equations:

1. \( x = 5 - 2y \)
2. \( 6y = 10 - 3x \)

Step 1: Substitute the expression for \( x \) from the first equation into the second equation.

From equation (1):
[tex]\[ x = 5 - 2y \][/tex]

Substitute \( x = 5 - 2y \) into equation (2):
[tex]\[ 6y = 10 - 3(5 - 2y) \][/tex]

Step 2: Simplify the equation obtained after substitution.

[tex]\[ 6y = 10 - 3(5 - 2y) \][/tex]
[tex]\[ 6y = 10 - 15 + 6y \][/tex]
[tex]\[ 6y = 6y - 5 \][/tex]

Step 3: Isolate the variable terms on one side of the equation.

Subtract \( 6y \) from both sides:
[tex]\[ 6y - 6y = -5 \][/tex]
[tex]\[ 0 = -5 \][/tex]

Step 4: Analyze the resultant equation.

The equation \( 0 = -5 \) is a contradiction. This suggests that there is no solution that satisfies both equations simultaneously.

Therefore, the system of equations has no solution. In other words, there are no values of [tex]\( x \)[/tex] and [tex]\( y \)[/tex] that satisfy both equations at the same time.