Which equation represents a line that passes through [tex]\left(2, -\frac{1}{2}\right)[/tex] and has a slope of 3?

A. [tex]y - 2 = 3 \left(x + \frac{1}{2} \right)[/tex]
B. [tex]y - 3 = 2 \left(x + \frac{1}{2} \right)[/tex]
C. [tex]y + \frac{1}{2} = 3(x - 2)[/tex]
D. [tex]y + \frac{1}{2} = 2(x - 3)[/tex]



Answer :

To determine which equation represents a line that passes through the point \(\left(2, -\frac{1}{2}\right)\) and has a slope of 3, we can use the point-slope form of the equation of a line.

The point-slope form is given by:
[tex]\[ y - y_1 = m(x - x_1) \][/tex]
where \((x_1, y_1)\) is a point on the line, and \(m\) is the slope of the line.

Given:
- The point \((x_1, y_1) = \left(2, -\frac{1}{2}\right)\)
- The slope \(m = 3\)

Substitute these values into the point-slope form:
[tex]\[ y - \left(-\frac{1}{2}\right) = 3(x - 2) \][/tex]

Simplify the left side of the equation:
[tex]\[ y + \frac{1}{2} = 3(x - 2) \][/tex]

This is the simplified form of the equation of the line that passes through \((2, -\frac{1}{2})\) with a slope of 3.

Thus, the correct option is:
[tex]\[ y + \frac{1}{2} = 3(x - 2) \][/tex]

Therefore, the answer is:
[tex]\[ y + \frac{1}{2} = 3(x - 2) \][/tex]