To balance the chemical equation [tex]\( \text{H}_3\text{PO}_4 + \text{NaBr} \rightarrow \text{HBr} + \text{Na}_3\text{PO}_4 \)[/tex], first balance the sodium (Na) atoms by placing a coefficient of 3 in front of NaBr, resulting in [tex]\( \text{H}_3\text{PO}_4 + 3\text{NaBr} \rightarrow \text{HBr} + \text{Na}_3\text{PO}_4 \)[/tex]. Then, balance the bromine (Br) atoms by placing a coefficient of 3 in front of HBr, giving [tex]\( \text{H}_3\text{PO}_4 + 3\text{NaBr} \rightarrow 3\text{HBr} + \text{Na}_3\text{PO}_4 \)[/tex]. All atoms are now balanced, and the final equation is [tex]\( \text{H}_3\text{PO}_4 + 3\text{NaBr} \rightarrow 3\text{HBr} + \text{Na}_3\text{PO}_4 \)[/tex]. This reaction is classified as a double displacement reaction, where the cations and anions of the reactants exchange places to form new products.
