poopey
Answered

What is the additive inverse of the polynomial?

[tex]\[ -7y^2 + x^2 y - 3xy - 7x^2 \][/tex]

A. [tex]\[ 7y^2 - x^2 y + 3xy + 7x^2 \][/tex]

B. [tex]\[ 7y^2 + x^2 y + 3xy + 7x^2 \][/tex]

C. [tex]\[ -7y^2 - x^2 y - 3xy - 7x^2 \][/tex]

D. [tex]\[ 7y^2 + x^2 y - 3xy - 7x^2 \][/tex]



Answer :

To find the additive inverse of a polynomial, you must change the sign of each term in the polynomial. Let's carefully go through each term of the polynomial \(-7y^2 + x^2y - 3xy - 7x^2\) and find its additive inverse.

### Original Polynomial
[tex]\[ -7y^2 + x^2y - 3xy - 7x^2 \][/tex]

### Steps to Find the Additive Inverse

1. Change the sign of \(-7y^2\):
The original term is \(-7y^2\). Changing the sign, it becomes:
[tex]\[ 7y^2 \][/tex]

2. Change the sign of \(x^2y\):
The original term is \(x^2y\). Changing the sign, it becomes:
[tex]\[ -x^2y \][/tex]

3. Change the sign of \(-3xy\):
The original term is \(-3xy\). Changing the sign, it becomes:
[tex]\[ 3xy \][/tex]

4. Change the sign of \(-7x^2\):
The original term is \(-7x^2\). Changing the sign, it becomes:
[tex]\[ 7x^2 \][/tex]

### Additive Inverse Polynomial
Putting all the terms together, the additive inverse of the polynomial \(-7y^2 + x^2y - 3xy - 7x^2\) is:
[tex]\[ 7y^2 - x^2y + 3xy + 7x^2 \][/tex]

So, the correct answer is:
[tex]\[ 7 y^2 - x^2 y + 3 x y + 7 x^2 \][/tex]