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Solve for \( x \).

Since the angles are congruent, we can set their equations equal to each other.

[tex]\[
\begin{aligned}
3x + 2 &= x + 28 \\
3x - x + 2 &= 28 \\
2x + 2 &= 28 \\
2x &= 26 \\
x &= 13
\end{aligned}
\][/tex]

Hint: Get the [tex]\( x \)[/tex]-terms together on one side of the equal sign. Subtract [tex]\( x \)[/tex] from each side of the equation. Then, solve for [tex]\( x \)[/tex].



Answer :

GinnyAnswer
To solve the equation \( 3x + 2 = x + 28 \):

1. Isolate the x-terms: We start by moving the terms involving \( x \) to one side of the equation. To do this, subtract \( x \) from both sides:
[tex]\[ 3x + 2 - x = x + 28 - x \][/tex]
Simplifying gives:
[tex]\[ 2x + 2 = 28 \][/tex]
The coefficient of \( x \) on the left side is now \( 2 \).

2. Isolate the constant terms: Next, we move the constant term on the left side to the right side by subtracting \( 2 \) from both sides:
[tex]\[ 2x + 2 - 2 = 28 - 2 \][/tex]
Simplifying gives:
[tex]\[ 2x = 26 \][/tex]

3. Solve for \( x \): Finally, to find the value of \( x \), divide both sides of the equation by \( 2 \):
[tex]\[ x = \frac{26}{2} \][/tex]
Which simplifies to:
[tex]\[ x = 13 \][/tex]

Therefore, the solution to the equation [tex]\( 3x + 2 = x + 28 \)[/tex] is [tex]\( x = 13 \)[/tex].

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