Answer :
Alright, let's systematically determine the order of electronegativity for the elements in each given set by placing them in decreasing order:
### Set (a): Al, Si, Mg
1. Compare the electronegativity values to arrange them in descending order:
- Silicon (Si)
- Aluminum (Al)
- Magnesium (Mg)
So, the order for set (a) is:
Si, Al, Mg
### Set (b): Sb, Sr, I
1. Compare the electronegativity values to arrange them in descending order:
- Iodine (I)
- Antimony (Sb)
- Strontium (Sr)
So, the order for set (b) is:
I, Sb, Sr
### Set (c): Cl, I, Br
1. Compare the electronegativity values to arrange them in descending order:
- Chlorine (Cl)
- Bromine (Br)
- Iodine (I)
So, the order for set (c) is:
Cl, Br, I
### Set (d): P, Si, Na
1. Compare the electronegativity values to arrange them in descending order:
- Phosphorus (P)
- Silicon (Si)
- Sodium (Na)
So, the order for set (d) is:
P, Si, Na
In conclusion, the elements in each set arranged in order of decreasing electronegativity are:
- (a) Si, Al, Mg
- (b) I, Sb, Sr
- (c) Cl, Br, I
- (d) P, Si, Na
### Set (a): Al, Si, Mg
1. Compare the electronegativity values to arrange them in descending order:
- Silicon (Si)
- Aluminum (Al)
- Magnesium (Mg)
So, the order for set (a) is:
Si, Al, Mg
### Set (b): Sb, Sr, I
1. Compare the electronegativity values to arrange them in descending order:
- Iodine (I)
- Antimony (Sb)
- Strontium (Sr)
So, the order for set (b) is:
I, Sb, Sr
### Set (c): Cl, I, Br
1. Compare the electronegativity values to arrange them in descending order:
- Chlorine (Cl)
- Bromine (Br)
- Iodine (I)
So, the order for set (c) is:
Cl, Br, I
### Set (d): P, Si, Na
1. Compare the electronegativity values to arrange them in descending order:
- Phosphorus (P)
- Silicon (Si)
- Sodium (Na)
So, the order for set (d) is:
P, Si, Na
In conclusion, the elements in each set arranged in order of decreasing electronegativity are:
- (a) Si, Al, Mg
- (b) I, Sb, Sr
- (c) Cl, Br, I
- (d) P, Si, Na