The task given appears to be a collection of unrelated mathematical expressions and equations. To make it sensible and readable, I'll format it into distinct, coherent problems.

Solve the following problems:

1. \( 53 \div 1.33 \approx 40 \, \text{m/s} \)

2. \( 5 \times 6 = 30 \)

3. [tex]\( 40 \times 6 = 240 \)[/tex]



Answer :

Let's break down the problem step-by-step to find the results for each of the given expressions.

1. The first expression given is \( 40 \, \text{m/s} \):
- This is a straightforward value and does not require any further calculation.
- Thus, the result of this expression is \( 40 \).

2. The second expression is \( 5 \times 6 \):
- Multiplication is an arithmetic operation where you add a number to itself a specified number of times. Here, we are multiplying 5 by 6.
- This means we are adding 5 together 6 times: \( 5 + 5 + 5 + 5 + 5 + 5 \).
- This results in \( 30 \).

3. The third expression is \( 40 \times 6 \):
- Again, we use multiplication to find the product of 40 and 6.
- This means adding 40 together 6 times: \( 40 + 40 + 40 + 40 + 40 + 40 \).
- This results in \( 240 \).

Thus, the detailed step-by-step solutions for the given expressions are:

- The value of \( 40 \, \text{m/s} \) is \( 40 \).
- The product of \( 5 \times 6 \) is \( 30 \).
- The product of \( 40 \times 6 \) is \( 240 \).

Therefore, the final results are:
[tex]\[ (40, 30, 240) \][/tex]