What are the solutions of the equation [tex]x^4 - 5x^2 - 36 = 0[/tex]? Use factoring to solve.

A. [tex]x= \pm 2[/tex] and [tex]x= \pm 3[/tex]
B. [tex]x= \pm 2i[/tex] and [tex]x= \pm 3[/tex]
C. [tex]x= \pm 2[/tex] and [tex]x= \pm 3i[/tex]
D. [tex]x= \pm 2i[/tex] and [tex]x= \pm 3i[/tex]



Answer :

To solve the equation \( x^4 - 5x^2 - 36 = 0 \) using factoring, we can proceed as follows:

1. Rewrite the equation: Start with the original equation:
[tex]\[ x^4 - 5x^2 - 36 = 0 \][/tex]

2. Substitute \( y = x^2 \): This substitution simplifies the polynomial:
[tex]\[ y^2 - 5y - 36 = 0 \][/tex]
Here, \( y = x^2 \).

3. Factor the quadratic equation: We need to factor \( y^2 - 5y - 36 = 0 \). We look for two numbers that multiply to \(-36\) and add to \(-5\). These numbers are \(-9\) and \(4\):
[tex]\[ y^2 - 5y - 36 = (y - 9)(y + 4) = 0 \][/tex]

4. Solve for \( y \): Set each factor equal to zero to solve for \( y \):
[tex]\[ y - 9 = 0 \quad \Rightarrow \quad y = 9 \][/tex]
[tex]\[ y + 4 = 0 \quad \Rightarrow \quad y = -4 \][/tex]

5. Back-substitute \( y = x^2 \): Replace \( y \) with \( x^2 \):
- For \( y = 9 \):
[tex]\[ x^2 = 9 \quad \Rightarrow \quad x = \pm 3 \][/tex]
- For \( y = -4 \):
[tex]\[ x^2 = -4 \quad \Rightarrow \quad x = \pm 2i \][/tex]

6. List the solutions: The solutions to the equation \( x^4 - 5x^2 - 36 = 0 \) are:
[tex]\[ x = \pm 3, \pm 2i \][/tex]

Thus, the correct answer is:
[tex]\[ x = \pm 2i \text{ and } x = \pm 3 \][/tex]

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