What are the solutions to the equation [tex]$0=x^2-x-6$[/tex]? Select two options:

A. [tex]$x=-3$[/tex]

B. [tex]$x=-2$[/tex]

C. [tex]$x=0$[/tex]

D. [tex]$x=2$[/tex]

E. [tex]$x=3$[/tex]



Answer :

To solve the quadratic equation \(0 = x^2 - x - 6\), we can use the factorization method:

1. Rewrite the equation:
[tex]\[ x^2 - x - 6 = 0 \][/tex]

2. Factor the quadratic expression: We need to find two numbers that multiply to \(-6\) (the constant term) and add up to \(-1\) (the coefficient of the middle term, \(x\)).

These two numbers are \(-3\) and \(2\) because:
[tex]\[ -3 \times 2 = -6 \quad \text{and} \quad -3 + 2 = -1 \][/tex]

3. Write the factored form of the quadratic expression:
[tex]\[ (x - 3)(x + 2) = 0 \][/tex]

4. Set each factor equal to zero and solve for \(x\):

[tex]\[ x - 3 = 0 \quad \Rightarrow \quad x = 3 \][/tex]
[tex]\[ x + 2 = 0 \quad \Rightarrow \quad x = -2 \][/tex]

So, the solutions to the equation \(0 = x^2 - x - 6\) are:
[tex]\[ x = -2 \quad \text{and} \quad x = 3 \][/tex]

Thus, the correct options are:
- \(x = -2\)
- [tex]\(x = 3\)[/tex]