Answer:
[tex] 4x^2\sqrt{2x} [/tex]
Step-by-step explanation:
[tex] \sqrt{32x^5} = \sqrt{16 \times 2 \times x^4 \times x} = \sqrt{4^2 \times 2 \times (x^2)^2 \times x} = 4x^2\sqrt{2x} [/tex]
