Which expression is equivalent to [tex]$7 x^2 \sqrt{2 x^4} \cdot 6 \sqrt{2 x^{12}}[tex]$[/tex], if [tex]$[/tex]x \neq 0$[/tex]?

A. [tex]$26 x^{22}$[/tex]
B. [tex]$13 x^{12} \sqrt{2}$[/tex]
C. [tex]$84 x^{10}$[/tex]
D. [tex]$42 x^{12} \sqrt{2}$[/tex]



Answer :

To find the expression equivalent to \(7 x^2 \sqrt{2 x^4} \cdot 6 \sqrt{2 x^{12}}\), let's go through the steps of simplification step by step.

First, we need to simplify the square roots within the expression.

1. Simplify \(\sqrt{2 x^4}\):
[tex]\[ \sqrt{2 x^4} = \sqrt{2} \cdot \sqrt{x^4} = \sqrt{2} \cdot x^2 \][/tex]

2. Simplify \(\sqrt{2 x^{12}}\):
[tex]\[ \sqrt{2 x^{12}} = \sqrt{2} \cdot \sqrt{x^{12}} = \sqrt{2} \cdot x^6 \][/tex]

Now, substitute these simplified forms back into the original expression:
[tex]\[ 7 x^2 \sqrt{2 x^4} \cdot 6 \sqrt{2 x^{12}} = 7 x^2 (\sqrt{2} \cdot x^2) \cdot 6 (\sqrt{2} \cdot x^6) \][/tex]

Next, combine like terms and constants:
[tex]\[ 7 x^2 \cdot \sqrt{2} \cdot x^2 \cdot 6 \cdot \sqrt{2} \cdot x^6 \][/tex]

First, multiply the constants:
[tex]\[ 7 \cdot 6 = 42 \][/tex]

Combine the square roots:
[tex]\[ \sqrt{2} \cdot \sqrt{2} = \sqrt{2^2} = \sqrt{4} = 2 \][/tex]

So the expression becomes:
[tex]\[ 42 x^2 \cdot x^2 \cdot x^6 \cdot 2 \][/tex]

Combine the terms with \(x\):
[tex]\[ x^2 \cdot x^2 \cdot x^6 = x^{2+2+6} = x^{10} \][/tex]

Now, multiply all components together:
[tex]\[ 42 \cdot 2 \cdot x^{10} = 84 x^{10} \][/tex]

Therefore, the equivalent expression is:
\[
\boxed{84 x^{10}}
\