Answer:
a = 0.78 m/s²
Explanation:
Let a = acceleration, u = initial velocity of the car = 10m/s, v = final velocity of the car = 15m/s and
s = distance covered = 80m.
Using equation of motion:
v² = u² + 2as
2as = v² - u²
[tex]a = \frac{ {v}^{2} - {u}^{2} }{2s} [/tex]
[tex]a = \frac{ {15}^{2} - {10}^{2} }{2 \times 80} = \frac{225 - 100}{160} [/tex]
[tex]a = \frac{125}{160} [/tex]
a = 0.78125 m/s²
a = 0.78 m/s²
The acceleration needed by a car is 0.78 m/s²
