Question 6 of 10

Which of the following is not a possible value for a probability?

A. [tex]\frac{11}{10}[/tex]

B. [tex]\frac{1}{10}[/tex]

C. [tex]\frac{1}{16}[/tex]

D. 0.001



Answer :

A probability is a measure of the likelihood that an event will occur and it ranges from 0 to 1, inclusive. This means that any valid probability must satisfy \(0 \leq P \leq 1\).

Let's analyze each of the given options to determine which one is not a possible value for a probability:

- Option A: \(\frac{11}{10}\)

\(\frac{11}{10}\) is a fraction that equals 1.1 when converted to a decimal. Since 1.1 is greater than 1, it does not fall within the range of allowable probability values. Therefore, \(\frac{11}{10}\) is not a possible value for a probability.

- Option B: \(\frac{1}{10}\)

\(\frac{1}{10}\) is a fraction that equals 0.1 when converted to a decimal. Since 0.1 falls between 0 and 1, it is a valid probability value.

- Option C: \(\frac{1}{16}\)

\(\frac{1}{16}\) is a fraction that equals 0.0625 when converted to a decimal. Since 0.0625 falls between 0 and 1, it is a valid probability value.

- Option D: 0.001

0.001 is already in decimal form and falls between 0 and 1. Hence, it is a valid probability value.

Given the analysis, the only option that is not a possible value for a probability is:

Option A: \(\frac{11}{10}\)

So, the correct answer is:
1.