Construct the requested confidence interval.

An electronics company just finished designing a new tablet computer and is interested in estimating its battery life. A random sample of 20 laptops with a full charge was tested, and the battery life was found to be approximately normal with a mean of 6 hours and a sample standard deviation of 1.5 hours.

Which of the following is the correct form for a [tex]$99 \%$[/tex] confidence interval?

A. [tex]$CI_{.99}(\mu) = 6 \pm 2.576(0.3354)$[/tex]
B. [tex]$CI_{.99}(\mu) = 6 \pm 2.576(1.5)$[/tex]
C. [tex]$CI_{.99}(\mu) = 6 \pm 2.861(0.3354)$[/tex]
D. [tex]$CI_{.99}(\mu) = 6 \pm 2.861(1.5)$[/tex]



Answer :

To construct the 99% confidence interval for the mean battery-life of the new tablet computer, we follow these steps:

1. Identify the Sample Statistics:
- Sample Mean (\(\bar{x}\)) = 6 hours
- Sample Standard Deviation (\(s\)) = 1.5 hours
- Sample Size (\(n\)) = 20

2. Calculate the Standard Error of the Mean:
The standard error (SE) is calculated using the formula:
[tex]\[ SE = \frac{s}{\sqrt{n}} \][/tex]
Substituting the values:
[tex]\[ SE = \frac{1.5}{\sqrt{20}} \approx 0.3354 \][/tex]

3. Determine the Critical Value:
For a 99% confidence interval and a sample size of 20, we use the t-distribution. The critical t-value corresponding to a 99% confidence level for 19 degrees of freedom (sample size - 1) is approximately 2.861.

4. Calculate the Margin of Error:
The margin of error (ME) is calculated using the formula:
[tex]\[ ME = t_{\frac{\alpha}{2}} \times SE \][/tex]
Substituting the values:
[tex]\[ ME = 2.861 \times 0.3354 \approx 0.9596 \][/tex]

5. Construct the Confidence Interval:
The confidence interval is given by:
[tex]\[ \bar{x} \pm ME \][/tex]
Substituting the values:
[tex]\[ 6 \pm 0.9596 \][/tex]

Therefore, the 99% confidence interval is approximately:
[tex]\[ (5.0404, 6.9596) \][/tex]

Matching this calculation with the given options, the correct form for the 99% confidence interval is:

[tex]\[ CI_{.99}(\mu) = 6 \pm 2.861(0.3354) \][/tex]

So, the correct choice is:

[tex]\[ CI_{.99}(\mu) = 6 \pm 2.861(0.3354) \][/tex]