In a large school, it was found that:

- $80\% $ of students are taking a math class.
- $77\% $ of students are taking an English class.
- [tex]$77\% $[/tex] of students are taking both.

To solve this problem, let's find the percentage of students taking either a math class, an English class, or both. We can use the Addition Rule for probabilities, which states:

[tex]\[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \][/tex]

Here, $ P(A \cup B) $ represents the probability (or percentage) of students taking either Math or English. $ P(A) $ is the percentage of students taking Math, $ P(B) $ is the percentage of students taking English, and $ P(A \cap B) $ is the percentage of students taking both Math and English.

Given:
- Percentage of students taking Math ($ P(A) $): $ 80\% $
- Percentage of students taking English ($ P(B) $): $ 77\% $
- Percentage of students taking both Math and English ($ P(A \cap B) $): $ 77\% $

We can substitute these values into the Addition Rule formula to find the percentage of students taking either Math or English:

[tex]\[ P(A \cup B) = 80\% + 77\% - 77\% \][/tex]

Perform the arithmetic:

[tex]\[ P(A \cup B) = 80\% \][/tex]

Thus, the percentage of students taking either a Math class or an English class or both is:

[tex]\[ 80\% \][/tex]

In conclusion:
- Percentage of students taking Math: $ 80\% $
- Percentage of students taking English: $ 77\% $
- Percentage of students taking both Math and English: $ 77\% $
- Percentage of students taking either Math or English or both: [tex]$ 80\% $[/tex]

In a large school, it was found that:- \(80\% \) of students are taking a math class.- \(77\% \) of students are taking an English class.- [tex]\(77\% \)[/tex] of students are taking both.

Answer :

Other Questions

In a large school, it was found that:

- \(80\% \) of students are taking a math class.
- \(77\% \) of students are taking an English class.
- [tex]\(77\% \)[/tex] of students are taking both.