The price of 9-volt batteries is increasing according to the function below, where [tex]t[/tex] is the number of years after January 1, 1980. During what year will the price reach [tex]\$4[/tex]?

[tex]P(t) = 1.1 \cdot e^{0.047 t}[/tex]

A. 2005
B. 2009
C. 2007
D. 2003



Answer :

To determine the year in which the price of 9-volt batteries will reach \$4 using the function \(P(t) = 1.1 \cdot e^{0.047t}\), follow these steps:

1. Set up the equation for the price goal:
[tex]\[ P(t) = 4 \][/tex]
Using the given function, substitute \(P(t)\):
[tex]\[ 1.1 \cdot e^{0.047t} = 4 \][/tex]

2. Solve for \(t\):
Divide both sides of the equation by 1.1:
[tex]\[ e^{0.047t} = \frac{4}{1.1} \][/tex]

3. Simplify the expression:
Calculate the right side:
[tex]\[ e^{0.047t} \approx 3.636 \][/tex]

4. Take the natural logarithm (ln) of both sides:
[tex]\[ \ln(e^{0.047t}) = \ln(3.636) \][/tex]
Using properties of logarithms:
[tex]\[ 0.047t = \ln(3.636) \][/tex]

5. Solve for \(t\):
[tex]\[ t = \frac{\ln(3.636)}{0.047} \][/tex]
Performing this calculation simplifies to:
[tex]\[ t \approx 27.4677485386290 \][/tex]

6. Determine the year:
Since \(t\) represents the number of years after 1980:
[tex]\[ \text{Year} = 1980 + t \approx 1980 + 27.4677485386290 \approx 2007 \][/tex]

Therefore, the price of 9-volt batteries will reach \$4 in the year 2007.

Thus, the correct answer is:

C. 2007

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