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[tex] \frac{7^{16}}{7^{12}}=\frac{7^{-18}}{?} [/tex]

The missing term in the denominator is:



Answer :

To solve the equation

[tex]\[ \frac{7^{16}}{7^{12}} = \frac{7^{-18}}{?} \][/tex]

we need to simplify and balance the exponents on both sides.

First, simplify the left-hand side:

[tex]\[ \frac{7^{16}}{7^{12}} = 7^{16-12} = 7^4 \][/tex]

So, the equation becomes:

[tex]\[ 7^4 = \frac{7^{-18}}{?} \][/tex]

To balance the equation, the exponents of 7 on both sides must be equal. This means:

[tex]\[ 7^4 = 7^{-18} / ? \][/tex]

Since the bases are the same, we can set the exponents equal to each other to find the missing term:

[tex]\[ 4 = -18 / ? \][/tex]

Solve for the missing term:

[tex]\[ ? = -18 / 4 = -4.5 \][/tex]

Therefore, the missing term in the denominator is

[tex]\[ \boxed{-4.5} \][/tex]