Rewrite as a single logarithm.

[tex]\[ 5 \log_t t - \log_t s \][/tex]

A. \(\log_t t^5 \div \log_t s\)
B. \(\log_t \frac{t^5}{s}\)
C. \(\log_t (t^5 - s)\)
D. [tex]\(\log_t \frac{5t}{s}\)[/tex]



Answer :

To solve the expression \(5 \log_t t - \log_t s\) and rewrite it as a single logarithm, follow these steps:

1. Evaluate \(5 \log_t t\):
Recall that \(\log_t t\) is the logarithm of \(t\) to the base \(t\). By definition, this is equal to 1.
[tex]\[ \log_t t = 1 \][/tex]
Therefore,
[tex]\[ 5 \log_t t = 5 \cdot 1 = 5 \][/tex]

2. Combine the logarithms:
Consider the properties of logarithms, specifically the one that allows multiplication to be expressed as addition and division as subtraction. For any base \( b \):
[tex]\[ a \log_b (x) = \log_b (x^a) \][/tex]
Applying this property, we get:
[tex]\[ 5 \log_t t = \log_t (t^5) \][/tex]

3. Rewrite the entire expression:
Combine \(\log_t (t^5)\) and \(- \log_t s\) using the logarithmic property for subtraction, which states:
[tex]\[ \log_b (a) - \log_b (b) = \log_b \left( \frac{a}{b} \right) \][/tex]
Thus, the expression \(5 \log_t t - \log_t s\) becomes:
[tex]\[ \log_t (t^5) - \log_t (s) = \log_t \left( \frac{t^5}{s} \right) \][/tex]

4. Final expression is:
[tex]\[ \log_t \left( \frac{t^5}{s} \right) \][/tex]

So, the correct answer is:
[tex]\[ \boxed{\text{B. } \log_t \frac{t^5}{s}} \][/tex]