Two resistors of resistances 30 and 60 are arranged in parallel. The current in the 30
resistor is 0.60 A.
What is the potential difference across the 602 resistor?
A 9.0 V
B 18 V
C 36 V
D
54 V



Answer :

Answer:

18V

Explanation:

When two resistors R1 and R2 are arranged in parallel then the effective/ total resistance

[tex] \frac{1}{ \: \:R_{ \:T}} = \frac{1}{ \ \: R_{1} } + \frac{1}{ \ \: R_{2} } [/tex]

[tex]\frac{1}{ \: \:R_{ \:T}} = \frac{1}{30} + \frac{1}{60} [/tex]

[tex]\frac{1}{ \: \:R_{ \:T}} = \frac{2 + 1}{60} [/tex]

[tex]\frac{1}{ \: \:R_{ \:T}} = \frac{3}{60} = \frac{ 1}{20} [/tex]

[tex]R_{ \:T} = 20 \: ohms[/tex]

From Ohm's law,

V = IR,

since 0.60A current passes through the 30 ohms resistor then the voltage across the 30 ohms

= 0.60 × 30

= 18 V.

Given that the resistors are arranged in parallel then same voltage is across the two resistors that is,

Voltage across 60 ohms = voltage across 30 ohms.

Voltage across 60 ohms = 18V