Answer:
Step-by-step explanation:
You want the amounts of $10807 invested at 12% and 5% if the interest from the former exceeds that from the latter by $580.63.
We can let x represent the amount invested at 12%. Then (10807-x) will be the amount invested at 5%. Interest earned is the product of the interest rate and the invested amount, so the difference in interest earned is ...
0.12x -0.05(10807 -x) = 580.63
0.17x -540.35 = 580.63 . . . . . . . . . . simplify
0.17x = 1120.98 . . . . . . . . . . . . . . add 540.35
x = 6594 . . . . . . . . . . . . . . . . . divide by 0.17
The remaining amount is invested at 5%:
10807 -6594 = 4213
$6594 is invested at 12%, and $4213 is invested at 5%.