Answer :
Certainly! Let's go through the step-by-step process for dividing 2187 by 3.
1. Set up the division:
```
729
3 ) 2187
```
2. Divide the first digit (2) by 3:
- 3 goes into 2, 0 times, so we look at the first two digits, 21.
3. Divide 21 by 3:
- 3 goes into 21, 7 times because \( 3 \times 7 = 21 \).
- Write 7 above the line.
- Subtract \( 21 \) from \( 21 \), which leaves \( 0 \).
- Bring down the next digit (8).
4. Divide the new number (8) by 3:
- 3 goes into 8, 2 times because \( 3 \times 2 = 6 \).
- Write 2 next to 7 above the line.
- Subtract \( 6 \) from \( 8 \), which leaves \( 2 \).
- Bring down the next digit (7).
5. Divide the new number (27) by 3:
- 3 goes into 27, 9 times because \( 3 \times 9 = 27 \).
- Write 9 next to 72 above the line.
- Subtract \( 27 \) from \( 27 \), which leaves \( 0 \).
6. Final quotient and remainder:
- The quotient is 729.
- The remainder is 0, since there is nothing left to bring down and we ended with a 0.
So, when you divide 2187 by 3, you get a quotient of 729 with a remainder of 0. The final answer is:
[tex]\[ 2187 \div 3 = 729 \, \text{remainder} \, 0 \][/tex]
1. Set up the division:
```
729
3 ) 2187
```
2. Divide the first digit (2) by 3:
- 3 goes into 2, 0 times, so we look at the first two digits, 21.
3. Divide 21 by 3:
- 3 goes into 21, 7 times because \( 3 \times 7 = 21 \).
- Write 7 above the line.
- Subtract \( 21 \) from \( 21 \), which leaves \( 0 \).
- Bring down the next digit (8).
4. Divide the new number (8) by 3:
- 3 goes into 8, 2 times because \( 3 \times 2 = 6 \).
- Write 2 next to 7 above the line.
- Subtract \( 6 \) from \( 8 \), which leaves \( 2 \).
- Bring down the next digit (7).
5. Divide the new number (27) by 3:
- 3 goes into 27, 9 times because \( 3 \times 9 = 27 \).
- Write 9 next to 72 above the line.
- Subtract \( 27 \) from \( 27 \), which leaves \( 0 \).
6. Final quotient and remainder:
- The quotient is 729.
- The remainder is 0, since there is nothing left to bring down and we ended with a 0.
So, when you divide 2187 by 3, you get a quotient of 729 with a remainder of 0. The final answer is:
[tex]\[ 2187 \div 3 = 729 \, \text{remainder} \, 0 \][/tex]