Answer :
Certainly! Let's add the fractions \(-\frac{4}{7}\) and \(\frac{3}{4}\) step by step.
Firstly, we need to find a common denominator for the fractions. The denominators here are 7 and 4. The least common multiple (LCM) of 7 and 4 is 28.
Next, we need to adjust both fractions so that they have this common denominator.
1. For \(-\frac{4}{7}\):
[tex]\[ -\frac{4}{7} = -\frac{4 \cdot 4}{7 \cdot 4} = -\frac{16}{28} \][/tex]
2. For \(\frac{3}{4}\):
[tex]\[ \frac{3}{4} = \frac{3 \cdot 7}{4 \cdot 7} = \frac{21}{28} \][/tex]
Now we can add these two fractions that have the same denominator:
[tex]\[ -\frac{16}{28} + \frac{21}{28} = \frac{-16 + 21}{28} = \frac{5}{28} \][/tex]
Thus, the sum of \(-\frac{4}{7}\) and \(\frac{3}{4}\) is:
[tex]\[ \frac{5}{28} \][/tex]
The answer in its simplest form is [tex]\(\frac{5}{28}\)[/tex].
Firstly, we need to find a common denominator for the fractions. The denominators here are 7 and 4. The least common multiple (LCM) of 7 and 4 is 28.
Next, we need to adjust both fractions so that they have this common denominator.
1. For \(-\frac{4}{7}\):
[tex]\[ -\frac{4}{7} = -\frac{4 \cdot 4}{7 \cdot 4} = -\frac{16}{28} \][/tex]
2. For \(\frac{3}{4}\):
[tex]\[ \frac{3}{4} = \frac{3 \cdot 7}{4 \cdot 7} = \frac{21}{28} \][/tex]
Now we can add these two fractions that have the same denominator:
[tex]\[ -\frac{16}{28} + \frac{21}{28} = \frac{-16 + 21}{28} = \frac{5}{28} \][/tex]
Thus, the sum of \(-\frac{4}{7}\) and \(\frac{3}{4}\) is:
[tex]\[ \frac{5}{28} \][/tex]
The answer in its simplest form is [tex]\(\frac{5}{28}\)[/tex].
Greetings!
Solve the question by simplifying the given expression:
[tex]-\frac{4}{7} +\frac{3}{4}[/tex]
Find the common denominator, which is 28 in this case. Therefore, multiply 7 by 4 in the first fraction to get 28 in the denominator and 4 by 7 in the second fraction to get 28 in the denominator. Remember, whatever action you do to the bottom, you must do the same for the top:
[tex]-\frac{4*4}{7*4} =-\frac{16}{28}[/tex]
[tex]-\frac{3*7}{4*7} =\frac{21}{28}[/tex]
[tex]-\frac{16}{28}+\frac{21}{28}[/tex]
Add the fractions:
[tex]-\frac{16}{28}+\frac{21}{28}=\frac{5}{28}[/tex]
Answer:
[tex]\boxed{\frac{5}{28}}[/tex]
