A toy rocket is launched straight up from the top of a building. The function that models the height as a function of time is [tex]h(t) = -16t^2 + 200t + 50[/tex]. At what height was the rocket launched?

A. 16 ft
B. 50 ft
C. 25 ft
D. 200 ft



Answer :

To find the height at which the toy rocket was launched, we need to evaluate the height function at the moment of launch. The rocket was launched at time \( t = 0 \). The height function is given as:

[tex]\[ h(t) = -16 t^2 + 200 t + 50 \][/tex]

We substitute \( t = 0 \) into the height function:

[tex]\[ h(0) = -16(0)^2 + 200(0) + 50 \][/tex]

Since \( 0^2 = 0 \) and \( 200 \times 0 = 0 \), the expression simplifies to:

[tex]\[ h(0) = 50 \][/tex]

Therefore, the height at which the rocket was launched is:

[tex]\[ 50 \, \text{ft} \][/tex]

So, the correct answer is:

[tex]\[ \boxed{50 \, \text{ft}} \][/tex]