Answered

What is the equation of a straight line that passes through (5,4) and (8,19). In the form of y=mx + c



Answer :

Answer:

[tex] \Large{\boxed{\sf y = 5x - 21 }} [/tex]

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Explanation:

Let's assume that we want to find the equation of the line that passes through A(5 , 4) and B(8 , 19) in slope-intercept form.

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[tex] \Large{\left[ \begin{array}{c c c} \underline{\tt Slope-Intercept \: Form \text{:}} \\ ~ \\ \tt y = mx + b \end{array} \right] } [/tex]

Where:

• m is the slope of the line.

• b is its y-intercept.

• (x , y) is a point on the line.

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Calculate the slope

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The first thing we have to do is calculate the slope of the line. To do that, we will use the slope formula, which is the following:

[tex] \left[ \begin{array}{c c c} \tt ~ \\ \tt m = \dfrac{\Delta y}{\Delta x} = \dfrac{y_B - y_{A}}{x_B - x_A}\\ \tt ~ \end{array} \right] [/tex]

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Let's identify our values and apply the formula:

[tex] \sf A(\underbrace{\sf 5}_{x_A} \ , \ \overbrace{\sf 4}^{y_A}) \ \ and \ \ B(\underbrace{\sf 8}_{x_B} \ , \ \overbrace{\sf 19}^{y_B}) \\ \\ \\ \sf \implies \sf m = \dfrac{19 - 4}{8 - 5} \\ \\ \implies \sf m = \dfrac{15}{3} = \dfrac{3 \ast 5}{3}\\ \\ \implies \boxed{\sf m = 5} [/tex]

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Find the y-intercept

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Substituting the value of the slope, the equation of the line becomes:

[tex] \sf y = 5c + b [/tex]

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Since the coordinates of all points on a line satisfy its equation, we can substitute the coordinates of one of the two given points into the equation and solve for b.

[tex] \sf A(\underbrace{\sf 5}_{x} \ , \ \overbrace{\sf 4}^{y} ) \\ \\ \implies \sf 4 = 5(5) + b \\ \\ \implies \sf 4 = 25 + b \Longleftrightarrow \boxed{\sf b = -21} [/tex]

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Therefore, the equation of the line in slope-intercept form is:[tex] \boxed{\boxed{\sf y = 5x - 21}} [/tex]

Answer:

→ y = 5x - 21

Step-by-step explanation:

Introduction

This question is asking us to determine an equation for a straight line, given that it passes through the points (5,4) and (8,19). The answer should be written in slope-intercept form (also known as y = mx + c or y = mx + b).

So first, we're going to apply our slope formula to determine the slope of this line.

The slope formula is:

[tex]\bigstar\quad\large\boldsymbol{m=\cfrac{y_2-y_1}{x_2-x_1}}[/tex]

Where:

  • m = slope
  • [tex]\sf (x_1,y_1)[/tex] is a point
  • [tex]\sf (x_2,y_2)[/tex] is another point

The first point is (5,4).

The second point is (8,19).

Substitute the values:

[tex]\sf m=\cfrac{19-4}{8-5}[/tex]

[tex]\sf m=\cfrac{15}{3}[/tex]

[tex]\sf m=5[/tex]

Therefore, the slope of this line is 5.

[tex]\dotfill[/tex]

Now we'll determine the line's equation. Start by using the point-slope formula:

[tex]\large\bigstar\quad\boldsymbol{y-y_1=m(x-x_1)}[/tex]

You can use any point, but I'll choose the first one: (5,4)

Substitute these values:

  • m is 5
  • [tex]y_1[/tex] is 4
  • [tex]x_1[/tex] is 5

[tex]\to\quad\sf y-4=5(x-5)[/tex]

[tex]\to\quad\sf y-4=5x-25[/tex]

[tex]\to\quad\sf y=5x-25+4[/tex]

[tex]\to\quad\sf y=5x-21[/tex]

Therefore, the equation of this line is: y = 5x - 21.

Have a nice day! :)