Construct a truth table for the compound statement.

[tex]$(q \wedge \sim p) \vee \sim q$[/tex]

\begin{tabular}{|c|c|c|c|c|c|c|}
\hline
[tex]$p$[/tex] & [tex]$q$[/tex] & [tex]$ \sim p $[/tex] & [tex]$ q \wedge \sim p $[/tex] & [tex]$ \sim q $[/tex] & [tex]$(q \wedge \sim p) \vee \sim q $[/tex] \\
\hline
T & T & F & F & F & F \\
\hline
T & F & F & F & T & T \\
\hline
F & T & T & T & F & T \\
\hline
F & F & T & F & T & T \\
\hline
\end{tabular}



Answer :

Sure, I can guide you step-by-step to construct the truth table for the compound statement \((q \wedge \sim p) \vee \sim q\).

Here is the step-by-step construction of the truth table:

1. Identify the possible values for \(p\) and \(q\).

2. Compute \(\sim p\): Negation of \(p\).

3. Compute \(q \wedge \sim p\): Logical AND between \(q\) and \(\sim p\).

4. Compute \(\sim q\): Negation of \(q\).

5. Compute \((q \wedge \sim p) \vee \sim q\): Logical OR between \(q \wedge \sim p\) and \(\sim q\).

Let's fill this in step-by-step:

[tex]\[ \begin{array}{|c|c|c|c|c|c|c|} \hline p & q & \sim p & q \wedge \sim p & \sim q & (q \wedge \sim p) \vee \sim q \\ \hline T & T & F & F & F & F \\ T & F & F & F & T & T \\ F & T & T & T & F & T \\ F & F & T & F & T & T \\ \hline \end{array} \][/tex]

Here's a breakdown of the row-wise calculations:

- First Row \((p = T, q = T)\):
- \(\sim p\): \(F\)
- \(q \wedge \sim p\): \(T \wedge F = F\)
- \(\sim q\): \(F\)
- \((q \wedge \sim p) \vee \sim q\): \(F \vee F = F\)

- Second Row \((p = T, q = F)\):
- \(\sim p\): \(F\)
- \(q \wedge \sim p\): \(F \wedge F = F\)
- \(\sim q\): \(T\)
- \((q \wedge \sim p) \vee \sim q\): \(F \vee T = T\)

- Third Row \((p = F, q = T)\):
- \(\sim p\): \(T\)
- \(q \wedge \sim p\): \(T \wedge T = T\)
- \(\sim q\): \(F\)
- \((q \wedge \sim p) \vee \sim q\): \(T \vee F = T\)

- Fourth Row \((p = F, q = F)\):
- \(\sim p\): \(T\)
- \(q \wedge \sim p\): \(F \wedge T = F\)
- \(\sim q\): \(T\)
- \((q \wedge \sim p) \vee \sim q\): \(F \vee T = T\)

Thus, the complete truth table for the given compound statement \((q \wedge \sim p) \vee \sim q\) is:

[tex]\[ \begin{array}{|c|c|c|c|c|c|c|} \hline p & q & \sim p & q \wedge \sim p & \sim q & (q \wedge \sim p) \vee \sim q \\ \hline T & T & F & F & F & F \\ T & F & F & F & T & T \\ F & T & T & T & F & T \\ F & F & T & F & T & T \\ \hline \end{array} \][/tex]