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A cannon ball is launched into the air with an upward velocity of 391 feet per second, from a 3-foot tall cannon. The height of the cannon ball after seconds can be found using the equation h(t)=16t^2+391t+3 Approximately how long will it take for the cannon ball to be 619 feet high? Round answers to the nearest tenth if necessary. units: How long long will it take to hit the ground? units:



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Luv2Teach

Answer:

Step-by-step explanation:

Your position equation is given as

[tex]h(t)=-16t^2+391t+3[/tex]

If you would like to find the time(s) that the object is 619 feet high, we have to fill in h(t) with 619 and do the algebra:

[tex]619=-16t^2+391t+3\\0=-16t^2+391t-616[/tex]  and then factor. It's easiest to use the quadratic formula for this. The 2 times are t = 1.7 s, 22.7 s

If we want to know how long the object is in the air, set h(t) equal to 0 and factor. Again, use the quadratic formula and the time is 24.4 s

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