[tex]$40.0 \, \text{mL}$[/tex] of [tex]$1.0 \, \text{M HCl}$[/tex] is added to a coffee cup. Then [tex]$0.486 \, \text{g Mg}$[/tex] are added. What is the mass of the solution?
[tex]\[
\begin{array}{c}
d_{\text{HCl}} = 1.02 \, \text{g/mL} \\
\text{Mass}_{\text{HCl}} = \frac{40.0 \, \text{mL}}{1} \times \frac{1.02 \, \text{g}}{\text{mL}} = 40.8 \, \text{g} \\
\text{Mass}_{\text{soln}} = 40.8 \, \text{g} + 0.486 \, \text{g}
\end{array}
\][/tex]