To identify which compound is inorganic among the given options, let's examine each compound carefully.
### Option A: \(C_6H_{12}O_6\)
This is the molecular formula for glucose, a simple sugar, which is an organic compound typically found in carbohydrates. Any compound with carbon and hydrogen bonds is generally considered organic.
### Option B: \(KH_2PO_4\)
This is the molecular formula for potassium dihydrogen phosphate, a compound commonly used in fertilizers and as a food additive. It does not contain carbon-hydrogen bonds, which indicates it is likely to be inorganic.
### Option C: \(CH_3COOH\)
This is the molecular formula for acetic acid, the main component of vinegar, and clearly an organic compound as it contains carbon-hydrogen bonds.
### Option D: \(C_2H_6\)
This is the molecular formula for ethane, a simple hydrocarbon, and it is an organic compound because it consists of carbon and hydrogen atoms.
### Option E: \(C_2H_5OH\)
This is the molecular formula for ethanol, a type of alcohol. Since it contains carbon-hydrogen bonds, it is an organic compound as well.
Based on the examination of the molecular formulas:
- Glucose (\(C_6H_{12}O_6\)) is organic.
- Potassium dihydrogen phosphate (\(KH_2PO_4\)) is inorganic.
- Acetic acid (\(CH_3COOH\)) is organic.
- Ethane (\(C_2H_6\)) is organic.
- Ethanol (\(C_2H_5OH\)) is organic.
Thus, the correct answer is B. [tex]\(KH_2PO_4\)[/tex], as it is the only inorganic compound among the given options.
