Answered

\begin{tabular}{|c|c|c|c|}
\hline
\multirow{2}{*}{\begin{tabular}{c}
Both \\
Gliders \\
Moving
\end{tabular}} & \multicolumn{2}{|c|}{\begin{tabular}{c}
Before \\
Collision
\end{tabular}} & \begin{tabular}{c}
After \\
Collision
\end{tabular} \\
\cline{2-4}
\begin{tabular}{c}
[tex]$m$[/tex] \\
[tex]$( kg )$[/tex]
\end{tabular} & 0.5 & 0.8 & 1.3 \\
\hline
\begin{tabular}{c}
[tex]$v$[/tex] \\
[tex]$( m / s )$[/tex]
\end{tabular} & 3.00 & -3.00 & -0.69 \\
\hline
\begin{tabular}{c}
[tex]$p$[/tex] \\
[tex]$( kg \cdot m / s )$[/tex]
\end{tabular} & 1.50 & -2.40 & -0.90 \\
\hline
\end{tabular}

Consider the example data provided to complete the sentences.

After colliding, [tex]$G1 + G2$[/tex] travels in a(n) [tex]$\square$[/tex] direction as [tex]$G1$[/tex] travels before the collision, but at about [tex]$\square$[/tex] [tex]$\square$[/tex] the magnitude in velocity. The initial momentum of [tex]$G2$[/tex] (the magnitude or absolute value) is greater than [tex]$G1$[/tex] because its [tex]$\square$[/tex] is greater than [tex]$G1$[/tex]. The percent difference between the total momentum before and after the collision is [tex]$\square$[/tex] [tex]$\%$[/tex].



Answer :

Alright, let's carefully examine the situation step-by-step with the given data and fill in the sentences appropriately.

### Step-by-Step Solution:

1. Determine Initial Conditions:
- Mass of Glider 1 (m1) = 0.5 kg
- Mass of Glider 2 (m2) = 0.8 kg
- Velocity of Glider 1 before collision (v1_before) = 3.00 m/s
- Velocity of Glider 2 before collision (v2_before) = -3.00 m/s

2. Calculate Momenta Before Collision:
- Momentum of Glider 1 before collision (p1_before) = m1 v1_before = 0.5 kg 3.00 m/s = 1.50 kg·m/s
- Momentum of Glider 2 before collision (p2_before) = m2 v2_before = 0.8 kg (-3.00 m/s) = -2.40 kg·m/s

3. Total Momentum Before Collision:
- Total momentum before collision = p1_before + p2_before = 1.50 kg·m/s + (-2.40 kg·m/s) = -0.90 kg·m/s

4. Conditions After Collision:
- Total mass after collision = m1 + m2 = 1.3 kg
- Velocity after collision (v_after) = -0.69 m/s
- Total momentum after collision (from the table) = -0.90 kg·m/s

5. Compare Directions:
After the collision, the gliders move together with a velocity of -0.69 m/s.
- Since the velocity after collision is negative, they travel in the same direction as Glider 1 before the collision (Glider 1 had a positive momentum, meaning it was initially moving in a positive direction before collision).

6. Magnitude of Velocity:
- The magnitude of the post-collision velocity (-0.69) is less than the velocity of Glider 1 before the collision (3.00 m/s).

7. Momentum Comparison:
- The momentum magnitude of Glider 2 before the collision (| -2.40 |) is greater than Glider 1 (| 1.50 |) because its mass is greater.

8. Percent Difference Between Total Momentum Before and After Collision:
- The calculated percent difference was found to be approximately \(3.700743415417187 \times 10^{-14} \%\), which is extremely close to zero, indicating conservation of momentum within a very small error margin.

### Filling in the Sentences:

After colliding, [tex]\( G1 + G2 \)[/tex] travels in a negative direction as [tex]\( G1 \)[/tex] travels before the collision, but at about one-fourth the magnitude in velocity. The initial momentum of [tex]\( G2 \)[/tex] (the magnitude or absolute value) is greater than [tex]\( G1 \)[/tex] because its mass is greater than [tex]\( G1 \)[/tex]. The percent difference between the total momentum before and after the collision is 3.700743415417187 \times 10^{-14} %.