The least value the highest number could be, when the sum of three consecutive numbers is greater than 60, is 20.
The sum of three consecutive numbers can be represented as x + (x+1) + (x+2). According to the question, this sum is greater than 60. Hence, x + (x+1) + (x+2) > 60. Solving this inequality, the minimum value that the highest number (x+2) could take is 20.
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