Answer:
Step-by-step explanation:
First, let’s get the base to be the same number. Then we can look at the exponents and compare!
8^y = 16^(y+2)
2^3y = 2^4(y+2)
3y = 4(y+2)
3y = 4y + 8
-y = 8
y = -8
Hope this helps!
Step-by-step explanation:
[tex]take \: log_{2} \: both \: side \\ \\ y \: log_{2}(8) = y log_{2}(16) + log2 \\ \\ y \times 3 = y \times 4 + 1 \\ \\ 4y - 3y = - 1 \\ \\ y = - 1[/tex]